2x^2+24x^2+64x=0

Solution for 2x^2+24x^2+64x=0 equation:

2x^2+24x^2+64x=0

We add all the numbers together, and all the variables

26x^2+64x=0

a = 26; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·26·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*26}=\frac{-128}{52}
=-2+6/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*26}=\frac{0}{52}
=0
$